Capgemini ADAPT 2022 – Count Character Frequency Problem Solution using Java

Capgemini ADAPT 2022 - Count Character Frequency Problem Solution using Java
Capgemini ADAPT 2022 - Count Character Frequency Problem Solution using Java

In this post, we will try to give a solution to an important problem of Capgemini ADAPT 2022. The solution to the Problem is – Count Character Frequency Solution using Java.

However, the solutions are provided for learning purposes only. Candidates must submit their own code during attending the Sprints.

Count Character Frequency Problem Description – Capgemini ADAPT:


Write a program in Java to accept a string. Count and display the frequency of each character present in the string. The character with multiple frequencies should be displayed only once.

Count Character Frequency Problem Solution:


import java.util.Scanner;

public class Source {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
System.out.println(“Enter a string:”);
String str = in.nextLine();
int len = str.length();
char seenArr[] = new char[len];
int freqArr[] = new int[len];
int idx = 0;

for (int i = 0; i < len; i++) {
char ch = str.charAt(i);

if (Character.isWhitespace(ch)) {
continue;
}

boolean seen = false;
for (int j = 0; j < idx; j++) {
if (ch == seenArr[j]) {
seen = true;
break;
}
}

if (seen) {
continue;
}

int f = 1;
for (int k = i + 1; k < len; k++) {
if (ch == str.charAt(k)) {
f++;
}
}

seenArr[idx] = ch;
freqArr[idx] = f;
idx++;
}

for (int i = 0; i < idx; i++) {
System.out.print(seenArr[i] + ” “);
}

System.out.println();
for (int i = 0; i < idx; i++) {
System.out.print(freqArr[i] + ” “);
}
}
}


Top Companies + Batchwise Hiring Drive:


TOP COMPANIES HIRING DRIVEBATCHWISE HIRING DRIVES
1. TCS OFF-CAMPUS DRIVES1. 2018 BATCH
2. INFOSYS OFF-CAMPUS DRIVES2. 2019 BATCH
3. COGNIZANT OFF-CAMPUS DRIVES3. 2020 BATCH
4. WIPRO OFF-CAMPUS DRIVES4. 2021 BATCH
5. CAPGEMINI OFF-CAMPUS DRIVES5. 2022 BATCH

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