Change Using Minimal Coins/Notes Problem Solution | Capgemini ADAPT Solution 2022

Change Using Minimal Coins/Notes Problem Solution in Java | Capgemini ADAPT 2022 Solution using Java
Change Using Minimal Coins/Notes Problem Solution in Java | Capgemini ADAPT 2022 Solution using Java

In this post, you will get the solution to the Capgemini ADAPT 2022 solution to the problem of Change Using Minimal Coins/Notes in Java. Capgemini ADAPT Java Solutions 2022, Change Using Minimal Coins/Notes.

Note: The solutions are provided for learning purposes only. 

Table of Contents

Change Using Minimal Coins/Notes Problem Description:


Ram needs to pay the school fees of his 6-year-old kid. As he is busy with his work, he is not finding time to go to school to make payments. His kid’s school doesn’t accept online payment. So he decided to send the fee amount through his kid. The available denominations of rupees or coins are 500, 50, 10, 5, and 1. Can you write a program to find the minimal number of coins or notes to be given to his kid?

Input and Output Format:

Input consists of a single integer that corresponds to the fee amount to be paid.

The output consists of an integer that corresponds to the minimal number of coins or rupee notes.

Print Invalid Input if the input value is negative.

Sample Input 1:

682

Sample Output:

8

Sample Input 2:

-2345

Sample Output 2:

Invalid Input

Execution Time Limit:

10 seconds

Capgemini ADAPT 2022 – Change Using Minimal Coins/Notes Problem Solution in Java:


import java.util.scanner;

class Source{

public static void main(String args[]){

int a;

int b = 0, c = 0, d = 0, e = 0, f = 0, g = 0;

Scanner sc = new Scanner(System.in);

a = sc.nextInt();

if(a>0){

while (a>0){

if(a – 500 >= 0){

b++;

a = a – 500;

}else if (a – 100 >= 0){

c++;

a = a – 100;

} else if (a – 50 >= 0){

d++;

a = a – 50;

} else if (a – 10 >= 0){

e++;

a = a – 10;

} else if (a – 5 >= 0){

f++;

a = a – 5;

} else {

g++;

a = a – 1;

}

}

System.out.println(b+c+d+e+f+g);

} else {

System.out.println(“Invalid Input”);

}

}

}

 

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