Instruments Problem Solution in Java | Capgemini ADAPT Solutions 2022

In this post, you will get the solution to the Capgemini ADAPT 2022 solution to the problem Instruments in Java. Capgemini ADAPT Java Solutions 2022, Instruments.

Note: The solutions are provided for learning purposes only. 

Instruments Problem Description:

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Create an abstract class Instruments which is having the abstract function play.

*Create three more subclasses from Instrument which is Piano, Flute, and Guitar.

*Override the play mentioned inside all three classes printing a message

*”Piano” for Piano Class

*”Flute” for Flute class

*”Guitar” for Guitar class

* You must not allow the user to declare an object of the Instrument class.

*Create an array of 10 Instruments.

*Assign different types of instruments to Instrument reference.

*Check for the polymorphic behaviour of the play method.

*Use the instance of the operator to print which object is stored at which index of the Instrument array.

Instruments Problem Solution in Java – Capgemini ADAPT 2022:

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import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;

abstract class Instrument 
{ 
abstract void play(); 
} 
class Piano extends Instrument {
@Override 
void play() { 
System.out.println("Piano");
}
}
class Flute extends Instrument
{ 
@Override 
void play() 
{ 
System.out.println("Flute"); 
} 
}
class Guitar extends Instrument 
{ 
@Override
 void play() 
{ 
System.out.println("Guitar");
 } 
}
public class Source{
public static void main(String[] args)
{
Scanner in = new Scanner(System.in);
Instrument[] is = new Instrument[10];

int a;
a = in.nextInt();
if(a == 1){
for(int i = 0; i < 10; i++){
is[i] = new Piano();
}
for(int i = 0; i < 10; i++){
is[i].play();
}
}
else if(a==2)
{
for(int i = 0; i < 10; i++)
{
is[i] = new Flute();
}
for(int i = 0; i < 10; i++){
is[i].play();
}
else
{
for(int i = 0; i < 10; i++)
{
is[i] = new Guitar();
}
for(int i = 0; i < 10; i++)
{
is[i].play();
}
}
}
}

 

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